VH=BIdnqAV_H = \frac{BId}{nqA}

Voltage developed across conductor in magnetic field due to Hall effect.

Variables

VH
Hall voltage
Transverse voltage
In SI units: kg·m²/(A·s³)
V
B
Magnetic field
Applied field
In SI units: kg/(A·s²)
T
I
Current
Current through conductor
A
d
Width
Width of conductor
Allowed values: greater than 0
m
n
Carrier density
Charge carriers per volume
Allowed values: greater than 0
m⁻³
q
Charge
Carrier charge
In SI units: A·s
C
A
Cross-section
Cross-sectional area
Allowed values: greater than 0
m²

Derivation

From balance of electric and magnetic forces on charge carriers: qE = qv_d B.

Your notes

0/5000

Check value

Round inputs run through this page's calculator. Use it to test your own working or a rearranged form. It is a test case, not a real-world example.

  • B = 2 T (Magnetic field)
  • I = 3 A (Current)
  • d = 4 m (Width)
  • n = 5 m⁻³ (Carrier density)
  • q = 6 C (Charge)
  • A = 7 m² (Cross-section)

Result: VH = 0.11428571 V

Other electricity & magnetism formulas with the same quantities

Where this formula is listed

Common questions

What is the Hall Voltage formula?

Hall Voltage is written V_H = BId/(nqA). Voltage developed across conductor in magnetic field due to Hall effect. It belongs to Electricity & Magnetism, under Magnetism.

What are the units in V_H = BId/(nqA)?

In SI units, V_H is hall voltage, measured in kg·m²/(A·s³); B is magnetic field, measured in kg/(A·s²); I is current, measured in A; d is width, measured in m; n is carrier density, measured in m⁻³; q is charge, measured in A·s; A is cross-section, measured in m².

How is the Hall Voltage formula derived?

From balance of electric and magnetic forces on charge carriers: qE = qv_d B. The result is V_H = BId/(nqA).