Optics

Microscope Magnification

M=−Lfo⋅DfeM = -\frac{L}{f_o} \cdot \frac{D}{f_e}

The total magnification of a compound microscope is the product of objective magnification (-L/f_o) and eyepiece magnification (D/f_e).

Variables

M
Total magnification
unitless
L
Tube length (distance between lenses)
Allowed values: greater than 0
m
fo
Focal length of objective
m
fe
Focal length of eyepiece
m
D
Near point distance (25 cm)
Allowed values: greater than 0
m

Derivation

The objective creates a real, inverted, magnified image at distance L from the objective. The eyepiece then acts as a magnifying glass on this intermediate image.

Your notes

0/5000

Check value

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  • L = 2 m (Tube length (distance between lenses))
  • fo = 3 m (Focal length of objective)
  • D = 4 m (Near point distance (25 cm))
  • fe = 5 m (Focal length of eyepiece)

Result: M = -0.53333333

Where this formula is listed

Common questions

What is the Microscope Magnification formula?

Microscope Magnification is written M = −L/f_o · D/f_e. The total magnification of a compound microscope is the product of objective magnification (-L/f_o) and eyepiece magnification (D/f_e). It belongs to Optics, under Optical Instruments.

What are the units in M = −L/f_o · D/f_e?

In SI units, M is total magnification (dimensionless); L is tube length (distance between lenses), measured in m; f_o is focal length of objective, measured in m; f_e is focal length of eyepiece, measured in m; D is near point distance (25 cm), measured in m.

How is the Microscope Magnification formula derived?

The objective creates a real, inverted, magnified image at distance L from the objective. The eyepiece then acts as a magnifying glass on this intermediate image. The result is M = −L/f_o · D/f_e.