Waves

Shock Wave Angle (Mach Cone)

sin(θ)=vsoundv=1M\sin(\theta) = \frac{v_{sound}}{v} = \frac{1}{M}

Half-angle of the Mach cone (shock wave) produced by supersonic object.

Variables

θ
Mach angle
Half-angle of Mach cone
rad
v_sound
Speed of sound
In the medium
m/s
v
Object velocity
Supersonic speed
m/s
M
Mach number
Must be > 1
unitless

Derivation

From geometry: sound wave travels v_sound·t while object travels v·t, forming cone with sin(θ) = v_sound/v.

Your notes

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Common questions

What is the Shock Wave Angle (Mach Cone) formula?

Shock Wave Angle (Mach Cone) is written sin(θ) = frac{vₛₒᵤₙd}{v} = 1/M. Half-angle of the Mach cone (shock wave) produced by supersonic object. It belongs to Waves, under Sound Waves.

What are the units in sin(θ) = frac{vₛₒᵤₙd}{v} = 1/M?

In SI units, θ is mach angle, measured in rad; v_sound is speed of sound, measured in m/s; v is object velocity, measured in m/s; M is mach number (dimensionless).

How is the Shock Wave Angle (Mach Cone) formula derived?

From geometry: sound wave travels v_sound·t while object travels v·t, forming cone with sin(θ) = v_sound/v. The result is sin(θ) = frac{vₛₒᵤₙd}{v} = 1/M.