Modern Physics

Electron Wavelength (Accelerated)

λ=h2meeV\lambda = \frac{h}{\sqrt{2m_e eV}}

Wavelength of an electron accelerated through potential V. Used in electron microscopy and diffraction experiments.

Variables

λ
de Broglie wavelength
Allowed values: greater than 0
m
h
Planck constant
Allowed values: greater than 0
J·s
me
Electron mass
Allowed values: greater than 0
kg
e
Electron charge
Allowed values: greater than 0
C
V
Accelerating voltage
Allowed values: greater than 0
V

Derivation

Combining kinetic energy eV = p²/2m with de Broglie relation λ = h/p.

Your notes

0/5000

Constants in this formula

h
6.626 070 15 × 10⁻³⁴. Exact by definition.
J·s
me
9.109 × 10⁻³¹. Measured (CODATA 2018).
kg
e
1.602 176 634 × 10⁻¹⁹. Exact by definition.
C

Check value

Round inputs run through this page's calculator, with each constant at its tabulated value. Use it to test your own working or a rearranged form. It is a test case, not a real-world example.

  • h = 6.626 070 15 × 10⁻³⁴ J·s (Planck constant)
  • me = 9.109 × 10⁻³¹ kg (Electron mass)
  • e = 1.602 176 634 × 10⁻¹⁹ C (Electron charge)
  • V = 2 V (Accelerating voltage)

Result: λ = 8.672324 × 10⁻¹⁰ m

Other modern physics formulas with the same quantities

Where this formula is listed

Common questions

What is the Electron Wavelength (Accelerated) formula?

Electron Wavelength (Accelerated) is written λ = h/√(2m_e eV). Wavelength of an electron accelerated through potential V. Used in electron microscopy and diffraction experiments. It belongs to Modern Physics, under Quantum Mechanics.

What are the units in λ = h/√(2m_e eV)?

In SI units, λ is de broglie wavelength, measured in m; h is planck constant, measured in J·s; m_e is electron mass, measured in kg; e is electron charge, measured in C; V is accelerating voltage, measured in V.

How is the Electron Wavelength (Accelerated) formula derived?

Combining kinetic energy eV = p²/2m with de Broglie relation λ = h/p. The result is λ = h/√(2m_e eV).