Electron Wavelength (Accelerated)
Wavelength of an electron accelerated through potential V. Used in electron microscopy and diffraction experiments.
Variables
Derivation
Combining kinetic energy eV = p²/2m with de Broglie relation λ = h/p.
Your notes
Constants in this formula
Check value
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- h = 6.626 070 15 × 10⁻³⁴ J·s (Planck constant)
- me = 9.109 × 10⁻³¹ kg (Electron mass)
- e = 1.602 176 634 × 10⁻¹⁹ C (Electron charge)
- V = 2 V (Accelerating voltage)
Result: λ = 8.672324 × 10⁻¹⁰ m
Other modern physics formulas with the same quantities
- Stopping Potential (Quantum Mechanics) shares Electron charge, Planck constant
- Compton Scattering (Quantum Mechanics) shares Planck constant, Electron mass
- Bohr Radius (Atomic Physics) shares Electron mass, Electron charge
- Photon Energy (Planck) (Quantum Mechanics) shares Planck constant
- Photoelectric Effect (Quantum Mechanics) shares Planck constant
- Particle in a Box Energy Levels (Quantum Mechanics) shares Planck constant
Where this formula is listed
- Modern Physics formulas, under Quantum Mechanics, alongside Heisenberg Uncertainty Principle, Energy-Time Uncertainty, Time-Dependent Schrödinger Equation, Photon Momentum and Fermi Energy.
- In the modern physics list it comes after Bragg's Law and before Bohr Radius.
- Modern Physics formula sheet, one of 41 formulas printed with symbol keys and SI units.
- The full formula index, grouped by category and topic.
Common questions
What is the Electron Wavelength (Accelerated) formula?
Electron Wavelength (Accelerated) is written λ = h/√(2m_e eV). Wavelength of an electron accelerated through potential V. Used in electron microscopy and diffraction experiments. It belongs to Modern Physics, under Quantum Mechanics.
What are the units in λ = h/√(2m_e eV)?
In SI units, λ is de broglie wavelength, measured in m; h is planck constant, measured in J·s; m_e is electron mass, measured in kg; e is electron charge, measured in C; V is accelerating voltage, measured in V.
How is the Electron Wavelength (Accelerated) formula derived?
Combining kinetic energy eV = p²/2m with de Broglie relation λ = h/p. The result is λ = h/√(2m_e eV).
