Mechanics

Work-Energy Theorem

Wnet=ΔKE=12mvf2−12mvi2W_{net} = \Delta KE = \frac{1}{2}mv_f^2 - \frac{1}{2}mv_i^2

Net work equals the change in kinetic energy.

Variables

Wnet
Net work
Total work done
In SI units: kg·m²/s²
J
ΔKE
Change in KE
Final minus initial KE
In SI units: kg·m²/s²
J
m
Mass
Object mass
Allowed values: 0 or more
kg
vf
Final velocity
Final speed
m/s
vi
Initial velocity
Initial speed
m/s

Derivation

Integrate F = ma over displacement.

Your notes

0/5000

Check value

Round inputs run through this page's calculator. Use it to test your own working or a rearranged form. It is a test case, not a real-world example.

  • m = 2 kg (Mass)
  • vf = 3 m/s (Final velocity)
  • vi = 4 m/s (Initial velocity)

Result: Wnet = -7 J

Other mechanics formulas with the same quantities

Where this formula is listed

Common questions

What is the Work-Energy Theorem formula?

Work-Energy Theorem is written W_net = ΔKE = (1/2)mv_f² − (1/2)mv_i². Net work equals the change in kinetic energy. It belongs to Mechanics, under Work & Energy.

What are the units in W_net = ΔKE = (1/2)mv_f² − (1/2)mv_i²?

In SI units, W_n et is net work, measured in kg·m²/s²; ΔKE is change in ke, measured in kg·m²/s²; m is mass, measured in kg; v_f is final velocity, measured in m/s; v_i is initial velocity, measured in m/s.

How is the Work-Energy Theorem formula derived?

Integrate F = ma over displacement. The result is W_net = ΔKE = (1/2)mv_f² − (1/2)mv_i².