Electricity & Magnetism

Electric Potential Energy

U=kq1q2r=qVU = k\frac{q_1 q_2}{r} = qV

Energy stored in configuration of charges.

Variables

U
Potential energy
Electric PE
In SI units: kg·m²/s²
J
k
Coulomb constant
8.99×10⁹
In SI units: kg·m³/(A²·s⁴)
Allowed values: greater than 0
N·m²/C²
q₁
Charge 1
First charge
In SI units: A·s
C
q₂
Charge 2
Second charge
In SI units: A·s
C
r
Distance
Separation
Allowed values: greater than 0
m
q
Charge
Test charge
In SI units: A·s
C
V
Potential
At charge location
In SI units: kg·m²/(A·s³)
V

Derivation

U = -∫F·dr = kq₁q₂/r. Also U = qV.

Your notes

0/5000

Constants in this formula

k
8.988 × 10⁹. Measured (from CODATA 2018 ε₀).
N·m²/C²

Check value

Round inputs run through this page's calculator, with each constant at its tabulated value. Use it to test your own working or a rearranged form. It is a test case, not a real-world example.

  • k = 8.988 × 10⁹ N·m²/C² (Coulomb constant)
  • q₁ = 2 C (Charge 1)
  • q₂ = 3 C (Charge 2)
  • r = 4 m (Distance)

Result: U = 1.3482 × 10¹⁰ J

Other electricity & magnetism formulas with the same quantities

Where this formula is listed

Common questions

What is the Electric Potential Energy formula?

Electric Potential Energy is written U = k(q₁q₂/r) = qV. Energy stored in configuration of charges. It belongs to Electricity & Magnetism, under Electrostatics.

What are the units in U = k(q₁q₂/r) = qV?

In SI units, U is potential energy, measured in kg·m²/s²; k is coulomb constant, measured in kg·m³/(A²·s⁴); q₁ is charge 1, measured in A·s; q₂ is charge 2, measured in A·s; r is distance, measured in m; q is charge, measured in A·s; V is potential, measured in kg·m²/(A·s³).

How is the Electric Potential Energy formula derived?

U = -∫F·dr = kq₁q₂/r. Also U = qV. The result is U = k(q₁q₂/r) = qV.