Mechanics

Free Fall

y=y0+v0t−12gt2y = y_0 + v_0 t - \frac{1}{2}gt^2

Vertical motion under gravity, neglecting air resistance.

Variables

y
Height
Vertical position
m
y₀
Initial height
Starting height
m
v₀
Initial velocity
Initial vertical velocity
m/s
g
Gravitational acceleration
≈ 9.8 m/s²
Allowed values: greater than 0
m/s²
t
Time
Elapsed time
s

Derivation

Special case of kinematic equation 2 with a = -g.

Your notes

0/5000

Constants in this formula

g
9.806 65. Exact by definition.
m/s²

Check value

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  • y₀ = 2 m (Initial height)
  • v₀ = 3 m/s (Initial velocity)
  • g = 9.806 65 m/s² (Gravitational acceleration)
  • t = 4 s (Time)

Result: y = -64.4532 m

Other mechanics formulas with the same quantities

Where this formula is listed

Common questions

What is the Free Fall formula?

Free Fall is written y = y₀ + v₀t − (1/2)gt². Vertical motion under gravity, neglecting air resistance. It belongs to Mechanics, under Kinematics.

What are the units in y = y₀ + v₀t − (1/2)gt²?

In SI units, y is height, measured in m; y₀ is initial height, measured in m; v₀ is initial velocity, measured in m/s; g is gravitational acceleration, measured in m/s²; t is time, measured in s.

How is the Free Fall formula derived?

Special case of kinematic equation 2 with a = -g. The result is y = y₀ + v₀t − (1/2)gt².