Mechanics

Projectile Range

R=v02sin⁡(2θ)gR = \frac{v_0^2 \sin(2\theta)}{g}

Horizontal range of a projectile launched from ground level.

Variables

R
Range
Horizontal distance traveled
m
v₀
Initial velocity
Launch speed
m/s
θ
Launch angle
Angle above horizontal
In SI units: rad
°
g
Gravitational acceleration
≈ 9.8 m/s²
Allowed values: greater than 0
m/s²

Derivation

Combine horizontal and vertical motion equations, solve for x when y = 0.

Your notes

0/5000

Constants in this formula

g
9.806 65. Exact by definition.
m/s²

Check value

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  • v₀ = 2 m/s (Initial velocity)
  • θ = 3 ° (Launch angle)
  • g = 9.806 65 m/s² (Gravitational acceleration)

Result: R = 0.04263575 m

Other mechanics formulas with the same quantities

Where this formula is listed

Common questions

What is the Projectile Range formula?

Projectile Range is written R = (v₀² sin(2θ))/g. Horizontal range of a projectile launched from ground level. It belongs to Mechanics, under Kinematics.

What are the units in R = (v₀² sin(2θ))/g?

In SI units, R is range, measured in m; v₀ is initial velocity, measured in m/s; θ is launch angle, measured in rad; g is gravitational acceleration, measured in m/s².

How is the Projectile Range formula derived?

Combine horizontal and vertical motion equations, solve for x when y = 0. The result is R = (v₀² sin(2θ))/g.