Mechanics

Projectile Time of Flight

T=2v0sin⁡(θ)gT = \frac{2v_0 \sin(\theta)}{g}

Total time a projectile spends in the air.

Variables

T
Time of flight
Total time in air
Allowed values: 0 or more
s
v₀
Initial velocity
Launch speed
m/s
θ
Launch angle
Angle above horizontal
In SI units: rad
°
g
Gravitational acceleration
≈ 9.8 m/s²
Allowed values: greater than 0
m/s²

Derivation

Time to reach max height is t = v₀sinθ/g. Total time is 2t.

Your notes

0/5000

Constants in this formula

g
9.806 65. Exact by definition.
m/s²

Check value

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  • v₀ = 2 m/s (Initial velocity)
  • θ = 3 ° (Launch angle)
  • g = 9.806 65 m/s² (Gravitational acceleration)

Result: T = 0.02134713 s

Other mechanics formulas with the same quantities

Where this formula is listed

Common questions

What is the Projectile Time of Flight formula?

Projectile Time of Flight is written T = (2v₀ sin(θ))/g. Total time a projectile spends in the air. It belongs to Mechanics, under Kinematics.

What are the units in T = (2v₀ sin(θ))/g?

In SI units, T is time of flight, measured in s; v₀ is initial velocity, measured in m/s; θ is launch angle, measured in rad; g is gravitational acceleration, measured in m/s².

How is the Projectile Time of Flight formula derived?

Time to reach max height is t = v₀sinθ/g. Total time is 2t. The result is T = (2v₀ sin(θ))/g.