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Mechanics
Mechanics

Projectile Maximum Height

H=v02sin⁡2(θ)2gH = \frac{v_0^2 \sin^2(\theta)}{2g}

Maximum height of a projectile.

Variables

H
Maximum height
Peak height reached
m
v₀
Initial velocity
Launch speed
m/s
θ
Launch angle
Angle above horizontal
°
g
Gravitational acceleration
≈ 9.8 m/s²
m/s²

Derivation

At max height, v_y = 0. Use v² = v₀² - 2gh.

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Common questions

What is the Projectile Maximum Height formula?

Projectile Maximum Height is written H = v₀² sin²(θ)/2g. Maximum height of a projectile. It belongs to Mechanics, under Kinematics.

What are the units in H = v₀² sin²(θ)/2g?

In SI units, H is maximum height, measured in m; v₀ is initial velocity, measured in m/s; θ is launch angle, measured in rad; g is gravitational acceleration, measured in m/s².

How is the Projectile Maximum Height formula derived?

At max height, v_y = 0. Use v² = v₀² - 2gh. The result is H = v₀² sin²(θ)/2g.