Thermodynamics
Helmholtz Free Energy
Maximum work extractable at constant T and V. Also denoted A.
Variables
FJ
Helmholtz free energy
Available work at const V,T
In SI units: kg·m²/s²
UJ
Internal energy
Total internal energy
In SI units: kg·m²/s²
TK
Temperature
Absolute temperature
Allowed values: greater than 0
SJ/K
Entropy
System entropy
In SI units: kg·m²/(s²·K)
Derivation
F = U - TS. At constant T,V: ΔF = ΔU - TΔS. Minimum F at equilibrium.
Your notes
0/5000
Check value
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- U = 2 J (Internal energy)
- T = 3 K (Temperature)
- S = 4 J/K (Entropy)
Result: F = -10 J
Other thermodynamics formulas with the same quantities
- Internal Energy (Ideal Gas) (First Law) shares Internal energy, Temperature
- Boltzmann Entropy (Entropy) shares Entropy
- Stefan-Boltzmann Law (Heat & Temperature) shares Temperature
- Work (Isothermal Process) (First Law) shares Temperature
- Ideal Gas Law (Kinetic Theory) shares Temperature
- Ideal Gas Law (Molecular) (Kinetic Theory) shares Temperature
Where this formula is listed
- Thermodynamics formulas, under Entropy, alongside Entropy Change (Ideal Gas).
- In the thermodynamics list it comes after Gibbs Free Energy.
- Thermodynamics formula sheet, one of 34 formulas printed with symbol keys and SI units.
- The full formula index, grouped by category and topic.
Common questions
What is the Helmholtz Free Energy formula?
Helmholtz Free Energy is written F = U − TS. Maximum work extractable at constant T and V. Also denoted A. It belongs to Thermodynamics, under Entropy.
What are the units in F = U − TS?
In SI units, F is helmholtz free energy, measured in kg·m²/s²; U is internal energy, measured in kg·m²/s²; T is temperature, measured in K; S is entropy, measured in kg·m²/(s²·K).
How is the Helmholtz Free Energy formula derived?
F = U - TS. At constant T,V: ΔF = ΔU - TΔS. Minimum F at equilibrium. The result is F = U − TS.
