Thermodynamics

Entropy Change (Ideal Gas)

ΔS=nCVln⁡TfTi+nRln⁡VfVi\Delta S = nC_V \ln\frac{T_f}{T_i} + nR\ln\frac{V_f}{V_i}

Entropy change for ideal gas between two states.

Variables

ΔS
Entropy change
Change in entropy
In SI units: kg·m²/(s²·K)
J/K
n
Moles
Amount of gas
mol
CV
Molar heat capacity
At constant volume
In SI units: kg·m²/(s²·mol·K)
J/(mol·K)
Tf
Final temperature
Final temp
K
Ti
Initial temperature
Initial temp
K
R
Gas constant
8.314
In SI units: kg·m²/(s²·mol·K)
J/(mol·K)
Vf
Final volume
Final volume
m³
Vi
Initial volume
Initial volume
m³

Derivation

dS = dQ/T = (nC_V dT + PdV)/T, integrate.

Your notes

0/5000

Constants in this formula

R
8.314 462 618…. Exact by definition.
J/(mol·K)

Other thermodynamics formulas with the same quantities

Where this formula is listed

Common questions

What is the Entropy Change (Ideal Gas) formula?

Entropy Change (Ideal Gas) is written ΔS = nC_V ln(T_f/T_i) + nR ln(V_f/V_i). Entropy change for ideal gas between two states. It belongs to Thermodynamics, under Entropy.

What are the units in ΔS = nC_V ln(T_f/T_i) + nR ln(V_f/V_i)?

In SI units, ΔS is entropy change, measured in kg·m²/(s²·K); n is moles, measured in mol; C_V is molar heat capacity, measured in kg·m²/(s²·mol·K); T_f is final temperature, measured in K; T_i is initial temperature, measured in K; R is gas constant, measured in kg·m²/(s²·mol·K); V_f is final volume, measured in m³; V_i is initial volume, measured in m³.

How is the Entropy Change (Ideal Gas) formula derived?

dS = dQ/T = (nC_V dT + PdV)/T, integrate. The result is ΔS = nC_V ln(T_f/T_i) + nR ln(V_f/V_i).