Thermodynamics

Ideal Gas Law (Molecular)

PV=NkBTPV = Nk_B T

Ideal gas law in terms of molecules.

Variables

P
Pressure
Gas pressure
In SI units: kg/(m·s²)
Allowed values: greater than 0
Pa
V
Volume
Container volume
Allowed values: greater than 0
m³
N
Number of molecules
Total molecules
Allowed values: greater than 0, whole number
unitless
kB
Boltzmann constant
1.38×10⁻²³
In SI units: kg·m²/(s²·K)
Allowed values: greater than 0
J/K
T
Temperature
Absolute temperature
Allowed values: greater than 0
K

Derivation

PV = NkT where N = nNₐ and k = R/Nₐ.

Your notes

0/5000

Constants in this formula

kB
1.380 649 × 10⁻²³. Exact by definition.
J/K

Check value

Round inputs run through this page's calculator, with each constant at its tabulated value. Use it to test your own working or a rearranged form. It is a test case, not a real-world example.

  • N = 2 (Number of molecules)
  • kB = 1.380 649 × 10⁻²³ J/K (Boltzmann constant)
  • T = 3 K (Temperature)
  • V = 4 m³ (Volume)

Result: P = 2.070974 × 10⁻²³ Pa

Other thermodynamics formulas with the same quantities

Where this formula is listed

Common questions

What is the Ideal Gas Law (Molecular) formula?

Ideal Gas Law (Molecular) is written PV = Nk_B T. Ideal gas law in terms of molecules. It belongs to Thermodynamics, under Kinetic Theory.

What are the units in PV = Nk_B T?

In SI units, P is pressure, measured in kg/(m·s²); V is volume, measured in m³; N is number of molecules (dimensionless); k_B is boltzmann constant, measured in kg·m²/(s²·K); T is temperature, measured in K.

How is the Ideal Gas Law (Molecular) formula derived?

PV = NkT where N = nNₐ and k = R/Nₐ. The result is PV = Nk_B T.