Thermodynamics

Mean Free Path

λ=kBT2πd2P\lambda = \frac{k_B T}{\sqrt{2}\pi d^2 P}

Average distance a molecule travels between collisions.

Variables

λ
Mean free path
Avg distance between collisions
Allowed values: greater than 0
m
kB
Boltzmann constant
1.38×10⁻²³
In SI units: kg·m²/(s²·K)
Allowed values: greater than 0
J/K
T
Temperature
Absolute temperature
Allowed values: greater than 0
K
d
Molecular diameter
Effective diameter
Allowed values: greater than 0
m
P
Pressure
Gas pressure
In SI units: kg/(m·s²)
Allowed values: greater than 0
Pa

Derivation

λ = 1/(√2 π d² n) where n = P/(kT).

Your notes

0/5000

Constants in this formula

kB
1.380 649 × 10⁻²³. Exact by definition.
J/K

Check value

Round inputs run through this page's calculator, with each constant at its tabulated value. Use it to test your own working or a rearranged form. It is a test case, not a real-world example.

  • kB = 1.380 649 × 10⁻²³ J/K (Boltzmann constant)
  • T = 2 K (Temperature)
  • d = 3 m (Molecular diameter)
  • P = 4 Pa (Pressure)

Result: λ = 1.726418 × 10⁻²⁵ m

Other thermodynamics formulas with the same quantities

Where this formula is listed

Common questions

What is the Mean Free Path formula?

Mean Free Path is written λ = (k_B T)/(√(2)πd²P). Average distance a molecule travels between collisions. It belongs to Thermodynamics, under Kinetic Theory.

What are the units in λ = (k_B T)/(√(2)πd²P)?

In SI units, λ is mean free path, measured in m; k_B is boltzmann constant, measured in kg·m²/(s²·K); T is temperature, measured in K; d is molecular diameter, measured in m; P is pressure, measured in kg/(m·s²).

How is the Mean Free Path formula derived?

λ = 1/(√2 π d² n) where n = P/(kT). The result is λ = (k_B T)/(√(2)πd²P).